Genius technique I have read arihant in that constraint relation is found by comparing lengths it consumes time this is excellent trick have u discivered it on ur own

T.s that is work done by tension. Since the string is inextensible , we can say that the work done by all the parts of tension should be 0. therfore T.s = 0 , on differentiating w.r.t time T.v = 0 , again on differentiating w.r.t time T.a = 0. quick and efficient.

a1/a2 and v1/v2 can be taken in any direction you wish.....you must only be careful to mark direction of tension(T) correctly and make sure you take product as Ta (if T and a are parallel) or -Ta (if antiparallel) or Ta*cosB (where B is angle between T and a)

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ReplyDeletesir why do we take submission T.a=0?

ReplyDeleteGenius technique I have read arihant in that constraint relation is found by comparing lengths it consumes time this is excellent trick have u discivered it on ur own

ReplyDeleteThis comment has been removed by the author.

Delete*belittle

Delete*belittle

DeleteT.s that is work done by tension.

ReplyDeleteSince the string is inextensible , we can say that the work done by all the parts of tension should be 0.

therfore T.s = 0 , on differentiating w.r.t time

T.v = 0 , again on differentiating w.r.t time

T.a = 0. quick and efficient.

Sir why we took a1 & a2 in upward direction.. In example 5 same as in example 2 v2 in downwards...?

ReplyDeletea1/a2 and v1/v2 can be taken in any direction you wish.....you must only be careful to mark direction of tension(T) correctly and make sure you take product as Ta (if T and a are parallel) or -Ta (if antiparallel) or Ta*cosB (where B is angle between T and a)

DeleteIs there any exception where this rule does not work

ReplyDelete