Your solution is wrong. In fact the question itself is incorrect. The electric field cannot be equal in areas of different resistance as in the above case.

Lol.. Yeah it's wrong. There is no conservative and non conservative E field, E field is E field. The question implies that area of cross section is constant, so resistivity changes and by J=Sigma.E, Electric field is different in both parts. In maxwell equations, E and B are non independent vectors, there is no 2 types of Electric fields

I think the question asked to find the conservative electric field produced in the ring. As the resistances are different in two equal parts, their electric fields cant be the same...

The problem has been solved by taking the currents in both the halves to be equal, at least in terms of magnitude. In such a case there should be no electrostatic field as no charge accumulation(equal currents) takes place.

Your solution is wrong. In fact the question itself is incorrect. The electric field cannot be equal in areas of different resistance as in the above case.

ReplyDeleteQuestion is correct because question is for conservative electric field not for induced electric field.

ReplyDeleteIt is similar as electric field inside battery from positive plate to negative plate while in resistor in direction of current.

ReplyDeleteLol.. Yeah it's wrong. There is no conservative and non conservative E field, E field is E field. The question implies that area of cross section is constant, so resistivity changes and by J=Sigma.E, Electric field is different in both parts. In maxwell equations, E and B are non independent vectors, there is no 2 types of Electric fields

ReplyDeleteI think the question asked to find the conservative electric field produced in the ring. As the resistances are different in two equal parts, their electric fields cant be the same...

ReplyDeleteThe problem has been solved by taking the currents in both the halves to be equal, at least in terms of magnitude. In such a case there should be no electrostatic field as no charge accumulation(equal currents) takes place.

ReplyDeleteHow then should one solve the problem ?